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Hungarian rosé wins prestigious U.S. wine award

The 2017 Sauska Rosé of Villány has been selected as “Best in Show” wine at The Rosé Competition 2018, under the auspices of the American Fine Wine Competition in Florida.

The judges of the the competition gave out numerous awards, but critically selected four Double Gold finalists for “Best in Show - Dry Rosé,” says a press release sent to the Budapest Business Journal. 

The final four were: 2017 Rodney Strong Vineyards from Russian River Valley, California (USD 25); 2017 Chateau LaFayette Reneau from the Finger Lakes, New York (USD 17); 2017 La Vieille Ferme, Vin de France, France (USD 10); and 2017 Sauska from Villány, SW Hungary (USD 15).

After careful deliberation, the judges picked Sauska from Hungary as “Best in Show - Dry Rosé.” The Sauska combined a unique blend of grapes that included Blaufrankisch (26%), Merlot (24%), Pinot Noir (19%), Cabernet Sauvignon (16%), Syrah (9%) and Cabernet Franc (6%).

“We canʼt believe we have won this competition,” said proprietor Andrea Sauska. “First ever American big wine award of our life. Thanks to you, dear American Fine Wine Competition, this competition is international, the judging fair and blind, and chances are equal.”

The Rosé Competition 2018 received a total of 173 entries and awarded 18 Double Gold Medals, 25 Gold Medals, and 92 Silver Medals. A list of all results can be found here.